ATTENTION ! May be best viewed by INTERNET EXPLORER 5.0 or HIGHER |
THE THEOREMS OF EL'AHIR STATES THAT ;
Binomial coefficient C(x,y) is given by
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PART-1
If
n 1 ,
a , b are integers such that;
k=a/b , and an angle
defined as ;
, Then
is a rational number , that
is ;
|
as a proof , we may state the following relation.
Since the right hand side of the equation is a
rational , is also
a rational.
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PART-2
If
n 1 ,
a , b are integers such that;
k=a/b , and an angle
defined as ;
ATTENTION n Being odd (n = 1,3,5......)
, Then
is
a rational number , that is ;
Provided that n is an odd integer . |
as a proof , we may state the following relation.
Since the right hand side of the equation is a rational
, is also
a
rational for odd n .
Please click here to see the related Mathematica program
PART-3
If
n 1 ,
a , b are integers such that;
,
and an argument
defined as ;
Then
is
a rational number that is ;
|
as a proof , we may state the following relation.
Since the right hand side of the equation is a rational
, is also
a rational.
Please click here to see the related Mathematica program
PART-4
If c is an odd integer 1 , then for the following equation ;
t is also an exact odd integer. |
As a proof , we may state the following relation for odd c ;
Right side is an exact odd
integer for odd c 1 so the
left side either.
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see the related Mathematica program.
PART-5
The nested transcendental chain of functions (Cos , Sin) ;
If (m) is any integer greater than one , (e.g 2 , 3 , 4 , 5 , 6 ............ )
And n1 , n2 , n3 ..................nj are integers of the type (4*k+1) , (e.g 5 , 9 , 13.....)
Then we have the following relations holding true;
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Nested transcendental chain of the first order (Cos , Sin) ;
f1(n,m) = Cos[n1 . ArcCos[m]]
f2(n,m) = Sin[n1 . ArcSin[m]]
Then f1(n,m) = f2(n,m) , (the expressions being equal to an integer )
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Nested transcendental chain of the second order (Cos , Sin) ;
f1(n,m) = Cos[n2 . ArcCos[Cos[n1 . ArcCos[m]]]]
f2(n,m) = Sin[n2 . ArcSin[Sin[n1 . ArcSin[m]]]]
Then f1(n,m) = f2(n,m) , (the expressions being equal to an integer )
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Nested transcendental chain of the third order (Cos , Sin) ;
f1(n,m) = Cos[n3 . ArcCos[Cos[n2 . ArcCos[Cos[n1 . ArcCos[m]]]]]]
f2(n,m) = Sin[n3 . ArcSin[Sin[n2 . ArcSin[Sin[n1 . ArcSin[m]]]]]]
Then f1(n,m) = f2(n,m) , (the expressions being equal to an integer )
Please click here to see the related Mathematica program.
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Nested transcendental chain of the j'th order (Cos , Sin) ;
f1(n,m) = Cos[nj .................................[n1 . ArcCos[m]]]]]...]
f2(n,m) = Sin[nj ................................. [n1 . ArcSin[m]]]]]....]
Then f1(n,m) = f2(n,m) , (the expressions being equal to an integer )